Question

Two supplementary angles differ by 44°. Find the angles.​

Answer 1

$\sf\huge\underline\blue{✴Question:-}$

If one of the complementary angles is 20 degrees and larger than 4 times the other, what are the angles?

$\sf\huge\underline\red{✴Solution:-}$

Let, one angle be x°, another angle y°

y= 4x + 20° (according to the condition)

➡(x+y)° = 90 ( complimentary angle)

➡x+ 4x + 20° = 90°

➡5x +20 = 90°

➡5x =( 90–20)°

➡5x = 70°

➡x = 70/5

x= 14°

➡y = 4x + 20

➡y = 4*14 + 20

➡y = 56 + 20

y = 76°

$\sf\huge\underline\red{Verification:-}$

(x+y = 14 +76 = 90° verified)$\sf\small\red{✔}$

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