Question

two supplementary angles differ by 48 degree. find its angles

Answer 1

let one angle be x another 180-x
their difference=48
a/c to question -
x-(180-x)=48
x-180+x=48
x+x=48+180
2x=180+48
2x=228
x=228➗2
x=114
180-x=180-114
=66
therefore the two angles are 114 and 66

Answer 2

Let the angles be x and x-48°.
It is given that they are supplementary.
Therefore
x + x - 48° = 180°.
2x = 228°.
x = 114°.
x - 48° = 114° - 48° = 66°.
Your required angle are 114° and 66°.