Question

Two supplementary angles differ by 48°.Find the angles.

Answer 1

Let the first angle be x
Then next angle is x + 48

So, x+x+48 = 180°
»2x + 48 =180°
» 2x = 180-48
» 2x = 132
» x= 132/2 = 66
So, one angle is 66° and other is 66+48 = 114°

Answer 2

let x be the angle
x+x+48=180
2x=180-48
2x=132
x=132/2
x=66
one angle=66 ,another angle=x+48
66+48=114