Question

two swimmers leave a point a on one bank of the river to reach point b lying right across on the other bank. one of them crosses the river along the straight line AB while the others swims at right angles to the steam and then walk the distance that he has been carried away by the stream to get point b.What was the velocity u of her walking if both swimmers reached the destination simultaneously? the stream velocity is 2 kilometre per hour and the velocity of each swimmer with respect to water is 2.5 km per hour​

Answer 1

Answer:

3km/hr

Hope It will HELPS You Buddy

❤❤❤❤❤

Explanation:

ANSWER

Let one of the swimmer (say 1) crosses the river along AB, which is obviously the shortest path. Time taken to cross the river by the swimmer 1.

t1=v′2−v02d, (where AB=d is the width of the river) (1)

For the other swimmer (say 2), which follows the quickest-path, the time taken to cross the river.

t2=v′d (2)

In the time t2, drifting of the swimmer 2, becomes

x=v0t2=v′v0d, (using equation 2) (3)

If t3 be the time for swimmer 2 to walk the distance x to come from C to B (shown in figure above), then 

t3=ux=v′uv0d (using equation 3) (4)

According to the problem t1=t2+t3

or, v′2−v02d=v′

Answer 2

Answer:

3 km is the answer

Explanation:

hope it helps you