Question

Two swimmers started simultaneously from the beach, one to south and the other to the east. two hours later the distance between them turned out to be 100 km. Find the speed of the faster swimmer, knowing that the speed of one of them was 75 % of the speed of the other:
(a) 30 kmph (b) 40 kmph
(c) 45 kmph (d) 60 kmph​

Answer 1

Answer:

answer must be 60kmph

hope it help!

Answer 2

Answer:

Correct option is (b) i.e. 40kmph

Step-by-step explanation:

Given: Two swimmers started simultaneously from the beach, one to south and the other to the east. two hours later the distance between them turned out to be 100 km.

Find: The speed of the faster swimmer, knowing that the speed of one of them was 75 % of the speed of the other:

(a) 30 kmph (b) 40 kmph

(c) 45 kmph (d) 60 kmph​

As shown in figure:

Distance between AB $=100km$

Since one is moving towards east and B towards south. So, the angle between them is $90^{o}$.

Using Pythagoras triplets which states Pythagorean triples are $a^{2} +b^{2} =c^{2}$ where a, b and c are the three positive integers. These triples are represented as (a,b,c). Here, a is the perpendicular, b is the base and c is the hypotenuse of the right-angled triangle.

So, distance OA $=80km$

Distance OB$=60km$

Speed of faster swimmer$=\frac{Distance}{Time}$

Distance=80km

therefore,

Speed of faster swimmer$=\frac{80}{2} kmph$

$=40kmph$

#SPJ2