Question

Two systems of monotonic ideal gas are separated by a diathermal wall. In system A there are 2 moles initially at 175 K, in system B there are 3 moles initially at 400 K. Write U_A​ and U_B​ as functions of R and the determine the common temperature (in Kelvin) after equilibrium is reached.

Answer 1

Answer:

U1=3/2×2×R×175

U2=5/2×3×R×400

since there is no heat loss to the surroundings,the internal energy lost by 2 is internal energy gained by 1

so equating both the equations we will get

6×(T-175)=15×(400-T)

on solving we get T=235.71K

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