Question

Two tables were bought at the same cost. One was sold at a profit of 5% and the other was sold at A loss of 7%. If the actual difference of the selling price were Rs.288, what is the cost price of? Each table

Answer 1

$\sf\large\underline\purple{Let:-}$

$\sf{\implies The\:cost\: price\:of\:_{(each\: table)}=x}$

$\sf\large\underline\purple{To\: Find:-}$

$\sf{\implies The\:cost\: price\:of\:_{(each\: table)}=?}$

$\sf\large\underline\purple{Solution:-}$

• To calculate the cost price of each table ,at first we have calculate the selling of each table then calculate the cost price of the table with the help of given difference in the question:

$\sf\large\underline\red{Calculate\:for\:(1st)\:table:-}$

$\sf\large\underline{Here\:\:P=5\%\:\:,CP=x:}$

$\tt{\implies SP=\dfrac{100+G\%}{100}*CP}$

$\tt{\implies SP=\dfrac{100+5}{100}*x}$

$\tt{\implies SP=\dfrac{105}{100}*x}$

$\tt{\implies SP=\dfrac{105x}{100}}$

$\sf\large\underline\red{Calculate\:for\:(2nd)\:table:-}$

$\sf\large\underline{Here\:\:L=7\%\:\:,CP=x:}$

$\tt{\implies SP=\dfrac{100-L\%}{100}*CP}$

$\tt{\implies SP=\dfrac{100-7}{100}*x}$

$\tt{\implies SP=\dfrac{93}{100}*x}$

$\tt{\implies SP=\dfrac{93x}{100}}$

• Now calculate the cost price of each table:-

$\tt{\implies Difference\:_{(1st\:sp-2nd\:sp)}=288}$

$\tt{\implies \dfrac{105x}{100}-\dfrac{93x}{100}=288}$

$\tt{\implies \dfrac{105x-93x}{100}=288}$

$\tt{\implies \dfrac{12x}{100}=288}$

$\tt{\implies 12x=288*100}$

$\tt{\implies x=24*100\implies x=2400}$

$\sf\large{Hence,}$

$\sf{\implies The\:cost\: price\:of\:_{(each\: table)}=Rs.2400}$

Answer 2

Pls mark as brainliest answer

CP is ₹ 2400