Math, asked by AmyCrystal, 1 day ago

Two tables were sold at ₹ 919 each, one at a profit of 10% and other at a loss of 10%. What are the cost price of each of the tables? In this sale, did the sellar make a profit or loss? What is the percentage of profit or loss?​​

Answers

Answered by naveenkarthickr1
1

Step-by-step explanation:

cost price of

first table 100/100+10×919

= 835.45

second table

100/100–90 × 919

1021.11

919×2=1838

1021.11+835.45=1856.56

1856.56−1838

= 18.56

seller did loss

The loss persentage is 1.037 approx

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Answered by BrainlyThemind
1

In 1st case

SP = ₹990

P = 10%

Let CP be ₹ 100

P = 10% of 100

= 10/100 × 100

= ₹ 10

SP = CP + P = 100 + 10 = 110

If SP is ₹ 110, CP = ₹ 100

If SP is ₹ 1, Cp = ₹ 100/110

If SP is ₹ 990, CP = ₹ 100/110 × 990 = ₹ 900

In 2nd case

SP = ₹ 990

L = 10 %

Let CP be ₹ 100

L = 10% of 100

= 10/100 × 100

= ₹ 10

SP = CP - L = 100 - 10 = 90

If SP is ₹ 90, CP = ₹ 100

If SP is ₹ 1, Cp = ₹ 100/90

If SP is ₹ 990, CP = ₹ 100/90 × 990 = ₹ 1100

Now,

Total SP = ₹ 990 + ₹ 990 = ₹ 1980

Total CP = ₹ 990 + ₹ 110 = ₹ 2000

Since, CP > SP

Loss = 2000 - 1980 = 20

Loss% = 20/2000 × 100 = 1%

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