Math, asked by tejarorasimran5479, 1 year ago

Two tables were sold at rupees 990 each one at a profit of 10% and the Bear the loss of 10% what are the cost price of each of the tables in this a seller makes a profit or loss what is the percentage of profit or loss

Answers

Answered by indusinghkancha
4

Case1: SP=₹990 Profit%=10% :. Since SP=CP+Pofit% of CP :. Putting value :.990=CP+10%of CP =>990=CP+\frac{10CP}{100} =>990=\frac{100CP+10CP}{100} =>990=\frac{110CP}{100} =>\frac{990×100}{110}=CP =>₹900=CP{ÆÑẞWĒR}............................(1) Case2: SP=₹990 Loss%=10% :. Since SP=CP-Loss% of CP :. Putting value :.990=CP-10%of CP =>990=CP-\frac{10CP}{100} =>990=\frac{100CP-10CP}{100} =>990=\frac{90CP}{100} =>\frac{990×100}{90}=CP =>₹1100=CP{ÆÑẞWĒR}.........................(2) Adding (1) and (2) :.Total CP=1100+900 :.Total CP=₹2000 SP of each article=₹990 Number of articles=2 :.Total SP=990×2 :.Total SP=₹1980 Since CP>SP :. Loss{ÆÑẞWĒR} :.Loss=CP-SP :. Putting value :.Loss=2000-1980 :.Loss=₹20 :.Loss%=\frac{Loss}{CP}×100 :. Putting value :.Loss%=\frac{20}{2000}×100 :.Loss%=1%{ÆÑẞWĒR}


govakanara111: Nice
Similar questions