Question

two tables with top faces as congruent trapezium are jointed as shown the length of the parallel side are 100 cm and 80 cm and the height is 45 cm find the combined table top area at the cost of polishing it rupees 350 per minute square

Answer 1

area of trapezium =1/2×h×(sum of parallel sides)

1/2×45 (100+80)

1/2×45×180

45×90

4050metre square

Answer 2

The combined table top area at the cost of polishing is Rs.2835000

Step-by-step explanation:

Length of parallel sides = 100 cm and 80 cm

Height of trapezium = 45 cm

Area of trapezium = $\frac{1}{2} (\text{Sum of parallel sides}) \times Height$

Area of trapezium = $\frac{1}{2} (100+80) \times 45$

Area of trapezium =4050 sq.cm.

Area of 2 trapezium = 2 \times 4050 = 8100  sq.cm.

Cost of polishing 1 sq.cm. = Rs.350

Cost of polishing 8100 sq.cm. = $8100 \times 350=Rs.2835000$

Hence the combined table top area at the cost of polishing is Rs.2835000

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