Two tailors, a and b, earn ` 300 and ` 400 per day respectively. a can stitch 6 shirts and 4 pairs of trousers while b can stitch 10 shirts and 4 pairs of trousers per day. to find how many days should each of them work and if it is desired to produce at least 60 shirts and 32 pairs of trousers at a minimum labour cost, formulate this as an lpp.
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Answer:
minimum labour cost = 2700
Step-by-step explanation:
suppose tailor A works for x days
and tailor B works for y days
First equation
6x + 10y = 60
Second equation
4x + 4y = 32
x = 60 -10y / 6
Put this in equation2
4x + 4y = 32
x + y = 8 (simplified)
60 -10y / 6 + y = 8
10 - 5/3y + y = 8
-5/3y + y = -2
-2/3y = -2
2/2y = 3
y = 3
put this value of y in equation 1
x =60 -10(3) / 6
x = 5
total labour
300x + 400y
300(5) + 400(3) = 2700
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