Two tangents can be drawn on the circle from the exterior point given in the image. What will be the
value of the expression
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Step-by-step explanation:
Draw a line segment, from Centre O to external point P { i.e. P is the intersecting point of both the tangents}
Now ∆POR and ∆POQ.
In order to prove they have the same length, we will first prove that both triangles are similar.
We know that the tangents make a right angle with a radius of the circle.
Here, OR and OQ is the radius of the circle
So, ∠OQP = ∠ORP = 90°
Now, it is clear that both the triangles ∆POQ and ∆POR are right-angled triangles and a common hypotenuse OP in them.
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