two tangents drawn from an external point to a circle are at right angles and measure 3.5cm each.the area of the circle is
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length of each tangent is 3.5 cm . Only the diameter can have two tangents subtending an angle of 90 .
so, 2r = root( 3.5^2 + 3.5^2) [ Using Pythagoras' theorem , here r is the radius of the circle .]
or , 2r = 3.5 x root(2)
or , 4r^2 = 3.5^2 x 2
or , r^2 = 3.5^2 / 2
now area of circle is pie x r^2
so area = 22/7 x 3.5^2 / 2 = 19.25 square units . Hence shown
so, 2r = root( 3.5^2 + 3.5^2) [ Using Pythagoras' theorem , here r is the radius of the circle .]
or , 2r = 3.5 x root(2)
or , 4r^2 = 3.5^2 x 2
or , r^2 = 3.5^2 / 2
now area of circle is pie x r^2
so area = 22/7 x 3.5^2 / 2 = 19.25 square units . Hence shown
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