Two tangents making an angle of 60° between them, are drawn to a circle of radius √2cm, then find the length of each tangent.
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Length of each tangent is 2.44
Radius of the circle = √2 cm (Given)
Angle of the tangents = 60° (Given)
Let the two tangents of circle be = PA and PB
Centre of the circle = O
Hence,
∠APO = ∠BPO = ∠APB/2
= 60/2
= 30
OA ⊥ AP and OB ⊥ BP.
In ΔOAP,
Tan 30 = OA/PA
1/√3 = √2/PA
PA = √3 ×√2
PA = √6
PA = 2.44
So, PA = PB = 2.44 cm.
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