two tangents PA and PB are drawn from an external point P to a circle with centre O.prove that OAPB is a cyclic quadrilateral
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given - PA and PB are two tangents from an external point P
therefore PA = PB
(tangents drwan from an external point to a circle are equal)
we have to proove that PAOB is a cyclic quadrilateral or angle APB + angle AOB = 180 °
therefore PA = PB
(tangents drwan from an external point to a circle are equal)
we have to proove that PAOB is a cyclic quadrilateral or angle APB + angle AOB = 180 °
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