Math, asked by sohankundu99, 9 months ago

Two tangents PA and PB are drawn from an external point P to a circle with centre O. Prove that PR = PA + AQ.

Answers

Answered by hk1466506
3

Answer:

ANSWER

In ΔPAC and ΔPBC

PA=PB

[length of tangents drawn from external point are equal ]

∠APC=∠BPC

[PA and PB are equally inclined to OP]

and PC=PC  [Common]

So, by SAS criteria of similarity

ΔPAC≅ΔPBC

⇒AC=BC and ∠ACP=∠BCP

But ∠ACP+∠BCP=180  

 

∴∠ACP+∠BCP=90  

 

Hence, OP⊥AB

Step-by-step explanation:

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