Two tangents PA and PB to a circle with centre O are inclined to each other at 70°. Find OAB
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Answer:
∠APB=70
o
∴ ∠APO=
2
1
∠APB
=
2
1
×70
=35
o
∠PAO=90
o
∴ In △OAP
∠OAP+∠APO+∠POA=180
o
∠AOP=180
o
−35−90
∠AOP=55
o
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