Two tangents PQ and PR are drawn to a circle with centre O from an external point P..Prove that angle QPR=2angle OQR.....
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As we know triangle qpo is similar to triangle pro
Hence angle 1=angle 2,angle 3=angle 4
Now in quad qpro
Angle 1+2+angle 3+4+angle oqp+angle orp=
360
Angle qor+qpr+90+90=360
Angle qor+qpr=180
Angle (1+2+3+4)=180
Angle(1+3)=90
Angle(2+4)=90
Hence angle 1=angle 2,angle 3=angle 4
Now in quad qpro
Angle 1+2+angle 3+4+angle oqp+angle orp=
360
Angle qor+qpr+90+90=360
Angle qor+qpr=180
Angle (1+2+3+4)=180
Angle(1+3)=90
Angle(2+4)=90
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