two tangents TP andTQ are drawn to a circle with centre O from an external point T prove that angle PTQ=2of angle OPQ
Answers
Answered by
2
we know that ,
OPT=90°
OPQ=90-QPT°⇒equation1
in ΔPQT
PTQ=180-2QPT IF 2 IS TAKEN AS COMMON
PTQ/2=90-QPT⇒EQUATION 2
From equations 1 and 2
PTQ/2=OPQ AS R.H.S are equal
PTQ=2OPQ
hence proved.
OPT=90°
OPQ=90-QPT°⇒equation1
in ΔPQT
PTQ=180-2QPT IF 2 IS TAKEN AS COMMON
PTQ/2=90-QPT⇒EQUATION 2
From equations 1 and 2
PTQ/2=OPQ AS R.H.S are equal
PTQ=2OPQ
hence proved.
Attachments:
akhilkick:
if you dont understand tell me if explain in full
if you like my answer mark as brainliest
Similar questions