two tankers contain 620l and840l of diesel respectively find the maximum capacity of a container which can measure the diesel of both the tankers in exact no of times
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Hey.
Since GCF (620, 840)= 2^2. 5^1 = 20
so, required container will be of 20 l.
Thanks.
Since GCF (620, 840)= 2^2. 5^1 = 20
so, required container will be of 20 l.
Thanks.
Answered by
1
620 = 2×2×5×31
840 = 2×2×2×3×5×7
HCF=2×2×5
=20l
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