two tankers contain 620litresand 840litres of diesel respectively find the maximum capacity of a container which can measure the diesel of both tankers in exact numbers of times
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Here we need to find the HCF(620,840)
620=5×2×2×31=2²×5×31
840=5×2×2×2×7×3=2³×3×5×7
so hcf=2²×5=20
620=5×2×2×31=2²×5×31
840=5×2×2×2×7×3=2³×3×5×7
so hcf=2²×5=20
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