Question

. Two tankers contain 750 litres and 450 litres of petrol, respectively. Find
the maximum capacity of a container which can measure the petrol of either
of the tankers in exact number of times.​

Answer 1

Answer:

Step-by-step explanation:

a similar question has the same answer

The capacity of required container will be obtained by finding the HCF of the capacity of tankers -

850 = 2×5×5×17

680 = 2×2×2×5×17

Common factors of 850 and 680 = {2,5,17}

HCF = 2×5×17

= 170

Answer 2

Given:-

Two tanks contains 750 litres and 450 litres of pertrol respectively.

Find:-

Maximum capacity of the container which can measure the pertol of the either of the tanks in exact number of times.

Solution:-

Here.. we have to calculate the HCF of 750 and 450.

First of all, let's find the LCM of each.

$\begin{array}{r|l} \\ 2 & 750 \\ \cline{2-2} 3 & 375 \\ \cline{2-2} 5 & 125 \\ \cline{2-2} 5 & 25 \\ \cline{2-2} 5 & 5 \\ \cline{2-2} & 1 \end {array}$

∴ LCM of 750 = 2 × 3 × 5 × 5 × 5

Similarly,

$\begin{array}{r|l} \\ 2 & 450 \\ \cline{2-2} 3 & 225 \\ \cline{2-2} 3 & 75 \\ \cline{2-2} 5 & 25 \\ \cline{2-2} 5 & 5 \\ \cline{2-2} & 1 \end {array}$

∴ LCM of 450 = 2 × 3 × 3 × 5 × 5

Now, HCF of 750 and 450 ..

LCM of 750 = 2 × 3 × 5 × 5 × 5

LCM of 450 = 2 × 3 × 3 × 5 × 5

2, 3 and 5 repeated in both

HCF of 750 and 450 = 2 × 3 × 5 × 5

∴ HCF of 750 and 450 is 150

Answer :-

150 litres