two tankers contain 850 ltrs and 680 ltrs of kerosene oil respectively find the maximum capacity of a container which can measure the kerosene oil of both tankers when used and exact number of times.
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Answered by
358
A
container can measure 850 liters of petrol an exact number of times(i.e. in integral multiple) if
its capacity in liters is a divisor of 850. Also to measure 680 liters
of petrol the capacity in liters must also be divisor of 680.
Therefore, the required maximum quantity of the container is the H.C.F of 850 L and 680 L.
Hence the maximum quantity of the container = 170 L.
Required number of times = (5+4) = 9. (Ans.)
Therefore, the required maximum quantity of the container is the H.C.F of 850 L and 680 L.
Hence the maximum quantity of the container = 170 L.
Required number of times = (5+4) = 9. (Ans.)
Answered by
350
Find the HCF between the two tanker that is
850=2×5²×17
680=2³×5×17
hcf is 2×5×17=170
Exact no of times=4+5=9
850=2×5²×17
680=2³×5×17
hcf is 2×5×17=170
Exact no of times=4+5=9
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