Two tankers contains 850l and 680l of petrol respectively. Find the maximum capacity of a container which can measure the petrol of either tanker in exact number of times
Answers
The capacity of required container will be obtained by finding the HCF of the capacity of tankers -
850 = 2×5×5×17
680 = 2×2×2×5×17
Common factors of 850 and 680 = {2,5,17}
HCF = 2×5×17
= 170
Answer) The container which can measure petrol of either tank exactly must be of 170 litres.
An alternate approach:
A container can measure 850 liters of petrol an exact number of
times(i.e. in integral multiple) if its capacity in liters is a divisor of 850.
Also to measure 680 liters of petrol the capacity in liters must also be
divisor of 680.
Therefore, the required maximum quantity of the container is the H.C.F of 850 L and 680 L.
Hence the maximum quantity of the container = 170 L.
Required number of times = (5+4) = 9.
Or Simply,
Find the HCF between the two tanker that is
850=2×5²×17
680=2³×5×17
hcf is 2×5×17=170
Exact no of times=4+5=9
Hope This Helps :)
Answer:
Given, the capacity of 1st tank =850 liters
And the capacity of 2nd tank= 680 liters
Now, the maximum capacity of a container which can measure the kerosene oil of both the
tankers when used an exact no.of times = HCF of 850 and 680
850 = 2 * 5 * 5 * 17
680 = 2 * 2 * 2 * 5 * 17
HCF(850, 680) = 2 * 5 * 17 = 170
Hence, the container which can measure petrol of either tank exactly must be of 170
liters.