Question

Two tanks are of the same capacity the dimensions of the first tank are 12 multiply 8 multiply 4 the second tank has a square base with depth 6cm find the side of the square

Answer 1

Hello users ....
solution:-
we know that:
volume of cuboid = l×b×h
where l is the length of rectangular tank or cuboid ,b is the breadth , and h is the height ,
and
1m² = 10⁴ cm²

also
the area of rectangle = l×b

According to given :
volume = l×b×h = 5.2m³
and
area of it's base = l× b = 2.6×10⁴ cm²

=> l× b = 2.6 m²

=> volume of cuboid
=> (area of base ) × h = 5.2 m³
=> h = 5.2 / 2.6 = 2 m

hence,
height of rectangular tank = 2m or 200 cm Answer

✡ hope it helps :)

Answer 2

Heya !

Here's your answer !!


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GIVEN THAT :

Two tanks have same capacity which means rhat their volumes are same.


Dimensions of 1st Tank :

Length : 12 cm

Breadth : 8 cm

Height : 4 cm

Dimensions of 2nd Tank :

Height : 6 cm

It's given that the base of 2nd tank is a square. Therefore, all sides of the base wil be equal.


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TO FIND :

Length of each Side of the square base.


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SOLUTION :

Let each side of square be x cm


We know,

Volume = l × b × h

Volume of 1st tank = 12 × 8 × 4 --------- 1

Volume of 2nd tank = x × x × 6 --------- 2



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From 1 and 2 , we get ,


=> 12 × 8 × 4 = x^2 × 6

=> x^2 = ( 12 × 8 × 4 )/6

=> x^2 = 2 × 8 × 4

=> x = $\sqrt{64}$

=> x = 8 cm


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ANSWER

Each side of the square base measures 8 cm.



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Thanks !!