Two tanks contain equal amounts of water. They are connected by a pipe and
3000 litres of water is pumped from one tank to the other. One tank then contains
6 times as much water as the other. How many litres of water did each tank contain
originally?
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Answer:
Both the tanks contained 4200 L of water originally.
Step-by-step explanation:
Let A be the volume of tank 1 and B be the volume of tank 2
Since both the tanks contained the same amount of water,
A = B
Let's say water is pumped from A to B
So tank 1 contains (A - 3000)L and tank 2 contains (B + 3000)L
Now it is said that this new volume of tank 2 equals 6 times the volume of tank 1
(B + 3000) = 6(A - 3000)
But A = B
Hence,
(A + 3000) = 6A - 18000
-5A = -21000
A = -21000 / -5
A = B = 4200 L
Hence, both the tanks contained 4200 L of water originally.
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