Math, asked by chanulkulatunga, 19 days ago

Two tanks contain equal amounts of water. They are connected by a pipe and
3000 litres of water is pumped from one tank to the other. One tank then contains
6 times as much water as the other. How many litres of water did each tank contain
originally?

Answers

Answered by kts182007
1

Answer:

Both the tanks contained 4200 L of water originally.

Step-by-step explanation:

Let A be the volume of tank 1 and B be the volume of tank 2

Since both the tanks contained the same amount of water,

A = B

Let's say water is pumped from A to B

So tank 1 contains (A - 3000)L and tank 2 contains (B + 3000)L

Now it is said that this new volume of tank 2 equals 6 times the volume of tank 1

(B + 3000) = 6(A - 3000)

But A = B

Hence,

(A + 3000) = 6A - 18000

-5A = -21000

A = -21000 / -5

A = B = 4200 L

Hence, both the tanks contained 4200 L of water originally.

Similar questions