Question

two tap a and b can fill tank in 10 hrs and 40hrs respectively .in how many hrs is the tank filled if both the tap were opened simultaneously?​

Answer 1

Let the hours taken by Tap A be x hours

Let the hours taken by Tap B be y hours

x=10hrs

y=40hrs.

(x+y)=50

Time taken by both taps= (x × y)/50

=(10×40)/50

=400/50

=8hrs

Therefore, time taken by taps to fill the tank simultaneously is 8 hrs.

Answer 2

Answer:

Therefore, time taken by taps to fill the tank simultaneously is 8 hrs.