two tap a and b can together fill a swimming pool in 15 day. A and B are kept for 12 days and then B is closed. It takes another 8 days for a pool to be filled. How many days does each tap require to fill the pool.?
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since taps a and b fill the pool together in 15 days.
the amount of water filled by both the tap in 1 day = 1/15 of pool
the water filled by both the taps in 12 days = 12/15 = 4/5
the remaining = 1 - 4/5
= 1/5 of the pool
now tap a fill 1/5 of the pool in 8 days.
therefore number of days in which tap "a" fill the pool = 81/5=40 days
the water filled by tap "a" in 1 day
= 1/40
the water filled by tap "b" in 1 day
= 115−140
=8−3120
=5120
=124
thus the number of days in which tap "b" fill the pool = 24 days
the amount of water filled by both the tap in 1 day = 1/15 of pool
the water filled by both the taps in 12 days = 12/15 = 4/5
the remaining = 1 - 4/5
= 1/5 of the pool
now tap a fill 1/5 of the pool in 8 days.
therefore number of days in which tap "a" fill the pool = 81/5=40 days
the water filled by tap "a" in 1 day
= 1/40
the water filled by tap "b" in 1 day
= 115−140
=8−3120
=5120
=124
thus the number of days in which tap "b" fill the pool = 24 days
dsayan:
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