Two tap a and b can together fill a swimming pool in 15 days the tap a and b are kept open for 12days and then the tap b closed it took another 8days for a to fill the pool how many days does each tap required to fill the pool
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since taps a and b fill the pool together in 15 days.
the amount of water filled by both the tap in 1 day = 1/15 of pool
the water filled by both the taps in 12 days = 12/15 = 4/5
the remaining = 1 - 4/5
= 1/5 of the pool
now tap a fill 1/5 of the pool in 8 days.
therefore number of days in which tap "a" fill the pool = 81/5=40 days
the water filled by tap "a" in 1 day = 1/40
the water filled by tap "b" in 1 day = 115−140=8−3120
=5120=124
thus the number of days in which tap "b" fill the pool = 24 days
hope this helps you
the amount of water filled by both the tap in 1 day = 1/15 of pool
the water filled by both the taps in 12 days = 12/15 = 4/5
the remaining = 1 - 4/5
= 1/5 of the pool
now tap a fill 1/5 of the pool in 8 days.
therefore number of days in which tap "a" fill the pool = 81/5=40 days
the water filled by tap "a" in 1 day = 1/40
the water filled by tap "b" in 1 day = 115−140=8−3120
=5120=124
thus the number of days in which tap "b" fill the pool = 24 days
hope this helps you
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