Math, asked by eektasharma37, 3 months ago

two tap can fill a tank in 15hr and 12hr respectively. how long would the two taps take to fill the empty tank if both of them are opend together



Answers

Answered by Anonymous
2

Answer:

Step-by-step explanation:

Given Two taps A and B can fill a tank in 5 hours and 20 hours respectively. If both the taps are open then due to a leakage, it took 30 minutes more to fill the tank. If the tank is full, how long will it take for the leakage alone to empty the tank?

In 1 hour, part filled by pipe A will be 1/5

In 1 hour, part filled by pipe B will be 1/20

So in 1 hour, A and B will fill the tank in 1/5 + 1/20 = 1/4

Now A and B together can fill the tank in 4 hours

It is given due to leakage it took 30 min more to fill the tank.

So the tank was filled in 4 30/60 hours = 4 ½ hours = 9/2.

Now total filled and leakage by pipe A and B will be 2/9 hours.

Again part emptied due to leakage in 1 hour will be

1/4 – 2/9

= 9 – 8 / 36

= 1/36

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Answered by Brainlyboy00
0

Answer:

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