Two taps A & B can together fill a swimming pool in 12 days.A and B are kept open for 10 days . then B is th closed. It takes Another 6 days for the pool to be filled. How many days tap requires to fill the pool ?
pls solve and send
Answers
Answer:
0
Step-by-step explanation:
hflyeotukwsydilelfsigitlarieyotuow eaitslyil
Given : Two taps A & B can together fill a swimming pool in 12 days.
A and B are kept open for 10 days . then B is closed.
It takes Another 6 days for the pool to be filled.
To Find : How many days tap A requires to fill the pool
Solution:
Two taps A & B can together fill a swimming pool in 12 days.
1/A + 1/B = 1/12
A and B are kept open for 10 days
Hence filled = 10/12 = 5/6
Remaining = 1- 5/6 = 1/6
A fills 1//6 in 6 days
Hence 6/A = 1/6 => A = 36
A takes 36 days to fill
1/36 + 1/B = 1/12
=> 1/B = 2/36
=> B = 18
B takes 18 days to fill
Learn More :
Pipe a pipe can fill a tank in 15 minutes and another one in 10 ...
brainly.in/question/14352511
A pipe can fill the tank in 20 min and another pipe can fill the tank
brainly.in/question/9388454
If two pipes function simultaneously, the reservoir will be filled in 12 ...
brainly.in/question/8254975