Two taps A and B can fill a cistern in 15 min and 20 min respectively. Then both are turned on at the same time. the tap A is turned off after some time, after that cistern is filled in 12 min. After how much a closed
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Part filled by both in 2 min = 2x(115+120)=2x(4+360)
=2×760=73
Part unfilled = 1−730=30−730=2330
Now, B fills 120 part in 1 min.
Therefore, 2330 part will be filled by B In
= (20×2330)min or i 463min
Therefore, Required time taken to fill the tank
=(2+463)=523min.
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