Question

Two taps a and b can fill a cistern in 28 min. And 42 min. Respectively. Third tap c can empty it in 42 min. If all the three taps are opened, the time taken to fill the cistern is:

Answer 1

Answer:

time taken to fill the cistern is 28 minutes

Step-by-step explanation:

C is minus because it will empty the tank

Answer 2

Given:  Two taps ‘A’ and ‘B’ can fill a cistern in 28 minutes and 42 minutes respectively. A third tap ‘C’ can empty it in 42 minutes.

all the three taps are open,

To Find :  the time taken to fill the cistern  

Solution:

Tap A can fill in 1 min = 1/28

Tap B can fill in 1 min = 1/42

Tap C can empty in 1 min  = 1/42

All taps together in 1 min = 1/28  + 1/42  -  1/42

= 1/28

Hence time taken to fill the tank =28 min

=28 mins

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