Question

Two taps ‘A’ and ‘B’ can fill a cistern in 28 minutes and 56 minutes respectively. A third tap ‘C’ can empty it in 42 minutes. If all the three taps are open, the time taken to fill the cistern will be?

Answer 1

Answer:

the answer will be correct

Answer 2

Given:  Two taps ‘A’ and ‘B’ can fill a cistern in 28 minutes and 56 minutes respectively. A third tap ‘C’ can empty it in 42 minutes.

all the three taps are open,

To Find :  the time taken to fill the cistern  

Solution:

Tap A can fill in 1 min = 1/28

Tap B can fill in 1 min = 1/56

Tap C can empty in 1 min  = 1/42

All taps together in 1 min = 1/28  + 1/56  -  1/42

= (  6 + 3 -  4   ) 168

= 5/168

Hence time taken to fill the tank = 168/5 min

= 33.6 mins

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