Two taps A and B can fill a cistern in 4 hours and 6 hours respectively. In the beginning, both taps are opened but after 2 hours first tap is turned off. How much longer will the tank take to fill?
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Step-by-step explanation:
work done by tap A in 1 hr= 1/4
work done by tap B in 1 hr= 1/6
work done by A+B in 1 hr=1/4+1/6
=3+2/12
=5/12
work done by A+B in 2 hrs=5/12×2
=5/6
Remain work=1-5/6
=6-5/6
=1/6
Remain work done by tap B= 1/6×6
=1hr
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