Question

Two taps a and b can fill a tank in 10 hours and 15 hours respectively. if both the taps are opened simultaneously, in how much time the tank will be filled

Answer 1

Both the taps together can fill the tank in 6 hr

Solution:

Given that,

Tap A can fill a tank in 10 hours

Tap B can fill a tank in 15 hours

Both the taps are opened simultaneously

In how much time the tank will be filled ?

In, 1 hour, Tap A can fill $\frac{1}{10}$ of tank

In, 1 hour, Tap B can fill $\frac{1}{15}$ of tank

Therefore, both A and B can fill,

$\frac{1}{10} + \frac{1}{15} = \frac{15+10}{150}\\\\\frac{1}{10} + \frac{1}{15} = \frac{25}{150}\\\\\frac{1}{10} + \frac{1}{15} = \frac{5}{30} = \frac{1}{6}$

Thus, in 6 hours A and B together can fill the tank

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