Question

two taps A and B can fill a tank in 10 hours and 40 hours respectively in how many hours in tank filled if both the taps where opened simultanususly​

Answer 1

Let the hours taken by Tap A be x hours
Let the hours taken by Tap B be y hours
x=10hrs
y=40hrs.
(x+y)=50
Time taken by both taps= (x×y)/50
=(10×40)/50
=400/50
=8hrs
Therefore, time taken by taps to fill the tank simultaneously is 8 hrs.