two taps A and B can fill a tank in 12 hours and 15 hours respectively and outlet pipe C can empty a tank in 10 hours find the time taken to empty a tank if all the three pipes are opened together
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So A is 20/15 = 1,33 times faster than B
and A is 12/15 = 0,8 times as fast outlet pipe
so in relation to A - we are using A’s time only everything else is in relation to A
Let X = time taken to fill tank
X ( 1 + 1/1,33 - 1/0,8) = 15
X ( 1 + 0,75 - 1,25) =15
0,5 X = 15
X = 30
so it will take 30 hours to fill the tank
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