two taps A and B can fill a tank in 6 and 9 hours respectively another tab C can empty the tank in 12 hours how long will it take to fill the tank if all the three are opend simultaneously
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0
Answer:
ok
Step-by-step explanation:
ok
Answered by
2
Answer:
Let x be the time of A tap
x+5 be the time of B tap
As per the statement the equation becomes,
x
1
+
x+5
1
=
6
1
Multiplying x(x+5) on both sides to eliminate the denominator.
6x+30+6x=x
2
+5x
x
2
−7x−30=0
On factoring, we get
(x−10)(x+3)=0
x=10 or −3
A tap to fill the tank separately is 10 hours.
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