Two taps A and B can fill a tank individually in 8 hrs and 12 hrs respectively. Both taps were opened at 10 am, when the tank was empty. After some time tap B was shut and it was observed that the tank was filled at 4 pm .
If after closing tap B, it is reopened after 60 min. then what would be the total time in min. to fill the tank completely ?
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Answer:
312 minutes
Step-by-step explanation:
Find out the efficiency of A and B
Take LCM of given time 8, 12
LCM = 24
Assume 24 unit is the total capacity of tank
A efficiency = 24/8 = 3
B efficiency = 24/12 = 2
Next if B tap is reopened after 60 minutes then,
A alone fill the tank for 1 hrs = 1*3 = 3 units
remaining units = 24- 3 = 21 unit
Means 21 unit is filled by A+B
then it takes time to fill the 21 unit = 21/5 = 4hr 12mintues
Total time = 1 hrs + 4hrs 12minutes
= 5hrs 12min
Convert 5hrs 12mintues into minutes
=> 5*60 + 12
=> 300 + 12
=> 312 minutes
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