Two taps A and B can fill a water tank in 6 and 9 hours respectively. Another tap C can empty the
whole tank in 12 hours. How long would they take to fill the tank if, by chance, all the three taps are
opened simultaneously?
please tell the answer fasttt
Attachments:
Answers
Answered by
6
Answer:
36/7 ≈ 5 hours
Step-by-step explanation:
Time Efficiency Total work =36 [LCM of 6, 9,12]
A--6 6
B--9 4
C-- (-12) (- 3)[ negative sign as C empties the tank]
ABC together takes = 36/(6+4-3) = 36/7
Answered by
5
Answer:
5 1/7
Step-by-step explanation:
Time efficiency total work = 36
L.C.M of 6,9,12
ABC together takes = 36/(6+4-3)
= 36/7
= 5 1/7 Answer
Similar questions