Question

Two taps A and B can together fill a swimming
pool in 12 days. A and B are kept open for 10
days and then Bis doned. It takes another 6 days
for the pool to be filled. How many days each tap
requires to fill the pool?​

Answer 1

I think so 5 days a pipe

........

Answer 2

$\huge\underline\frak\green{Question:}$

Two taps A and B can together fill a swimming

pool in 12 days. A and B are kept open for 10

days and then Bis doned. It takes another 6 days

for the pool to be filled. How many days each tap

requires to fill the pool?

$\huge\underline\frak\green{Answer:}$

I would like solve above problem by assuming A and B are two persons, they love to eat same number of chocolates everyday.

Let assume Swimming fool as an Box of Chocolates.

If both eat the chocolates regularly they will finish it in 15 days.

But A and B had chocolates regularly for 12 days, A planned for dieting so B finished remaining chocolates in the same rate as regular.

If A and B had chocolates regularly they would have finish remaining chocolates in 3 days (15–12), but B took 8 days to finish remaining chocolates.

Here u should have to use logic to assume remaining chocolates, I will assume remaining chocolates as 3*8= 24. (I assumed 24 because if divide 24 by 3 or 8 we will get a whole number).

B took 8 days to finish 24 chocolates, so B used to eat 3 chocolates per day.

Assume A and B together had the remaining chocolates they finish it in (15–12) 3 days, so A and B together eat (24/3) 8 chocolates per day.

A alone used to eat (8–3) 5 chocolates per day.

We assumed cofactors as 8 while finding the remaining chocolates, same way we need to find total numbers of chocolates that Box contains is 8×15=120 chocolates.

A requires 120/5 days. ie 24 days.

A requires 120/5 days. ie 24 days.B requires 120/3 days. ie 40 days.