Math, asked by supeshmankar93, 10 months ago

two taps A and B can together fill a swimming pool in 15 days.
A and B are kept open for 12 days and then B is closed. if it takes another 8 days for the pool to be filled. how many days each tap requires to fill the pool​

Answers

Answered by musicinmysoul
2

Answer:

a= 40

b= 24

Step-by-step explanation:

Let A and B be the rates of the 2 taps.

Equation:

15A + 15B = 1 job

20A + 12B = 1 job

Multiply thru the top equation by 12

multiply thru the bottom equation by 15

180A + 180B = 12

300A + 180B = 15

Subtract and solve for A

120A = 3

A = 1/40 job/day (A's rate)

A would take 40 days to fill the pool alone.

Solve for "B"

20A + 12B = 1

1/2 + 12B = 1

12B = 1/2

B = 1/24 job/day (B's rate)

Question

two taps A and B can together fill a swimming pool in 15 days.

A and B are kept open for 12 days and then B is closed. if it takes another 8 days for the pool to be filled. how many days each tap requires to fill the pool​

A would take 24 days to fill the pool alone. 

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