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Two taps A and B can together fill a swimming pool in 15 days. A and B are kept open for 12 days and
then B is closed. It takes another 8 days for the pool to be filled. How many days does each tap require to
fill the pool?
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Answer:
96 days
Step-by-step explanation:
a+b = 15 days
now,they are opened for 12 days =
a+b=12
then a is closed
rather than taking 15 days ( as tap a was closed), then
b=8=
3 days which had to be taken was 12%3= 25÷ of 15 days
time required to fill the pool by single tap=3×4=12×8=96 days will be required to fill the fu ckin g pool by single tap a or b
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