Math, asked by vijaybbhamare, 11 months ago

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Two taps A and B can together fill a swimming pool in 15 days. A and B are kept open for 12 days and
then B is closed. It takes another 8 days for the pool to be filled. How many days does each tap require to
fill the pool? ​

Answers

Answered by veenadubeyshukla82
1

Answer:

96 days

Step-by-step explanation:

a+b = 15 days

now,they are opened for 12 days =

a+b=12

then a is closed

rather than taking 15 days ( as tap a was closed), then

b=8=

3 days which had to be taken was 12%3= 25÷ of 15 days

time required to fill the pool by single tap=3×4=12×8=96 days will be required to fill the fu ckin g pool by single tap a or b

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