Question

Two taps A and B can together fill a swimming pool in 15 days. The tap A and B are kept open for 12 days and then tap Bis closed.It took another 8 days for tapA to fill the pool.How many days does each tap require to fill the pool

Answer 1

Let A and B be the rates of the 2 taps.

Equation:
15A + 15B = 1 job

20A + 12B = 1 job

Multiply thru the top equation by 12
multiply thru the bottom equation by 15

180A + 180B = 12
300A + 180B = 15

Subtract and solve for A
120A = 3
A = 1/40 job/day (A's rate)
A would take 40 days to fill the pool alone.

Solve for "B"
20A + 12B = 1
1/2 + 12B = 1
12B = 1/2
B = 1/24 job/day (B's rate)
A would take 24 days to fill the pool alone. 

Answer 2

Answer:

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