Question

Two taps A and B can together fill a
Swimming pool in 15 days. Taps A and B are
kept open for 12 days and then tap B is
closed. It takes another 8 days for the pool to
be filled. How many days does each tap
tap
require to fill the pool?​

Answer 1

Answer:

Please mark me brainliest. answer is below

Step-by-step explanation:

Let A and B be the rate of two taps

According to the question

15A+15B=1job..........(i)

20A+12B=1job.........(ii)

Multiply (i) by 12 and (ii) by 15

180A+180B=12...........(iii)

300A+180B=15.........(iv)

Subtract (iii) from (iv) we get

120A=3

A=  1/40  job/day

A would take 40 days to fill the pool alone

20A+12B=1

1/2 +12B=1

12B=  1/2    

B=  1/24  job/day

B would take 24 days to fill the pool alone