two taps A and B can together fill a swimming pool in 15 days. taps A and B are kept open for 12 days and then tap B is closed. it takes another 8 days for a pool to be filled how many days does each tap required to fill the pool?
Answers
A and B kept open for 12 days
work done in 12 days = 12/15 = 4/5
Work remaining = 1 - 4/5 = 1/5
A completed 1/5 work in 8 days
A will complete whole work alone in 40 days
A and B did in 12 days
A alone did in 40 days
B alone will do in
One day work of A and B together = 1/15
One day work of A = 1/40
One day work of B = X
1/(A+B) - 1/A = 1/B
1/15 - 1/40 = 1/x
(8 - 3) / 120 = 1/x
5/120 = 1/x
1/24 = 1/x
x = 24
So B alone can do it in 24 days
A and B kept open for 12 days
work done in 12 days = 12/15 = 4/5
Work remaining = 1 - 4/5 = 1/5
A completed 1/5 work in 8 days
A will complete whole work alone in 40 days
A and B did in 12 days
A alone did in 40 days
B alone will do in
One day work of A and B together = 1/15
One day work of A = 1/40
One day work of B = X
1/(A+B) - 1/A = 1/B
1/15 - 1/40 = 1/x
(8 - 3) / 120 = 1/x
5/120 = 1/x
1/24 = 1/x
x = 24
So B alone can do it in 24 days