Question

Two taps A and B can together fill a swimming pool in 15 days. The taps A and B are kept open for 12 days and then the tap B is closed. It took another 8 days for tap A to fill the pool. How many days does each tap require to fill the pool?

by using method of simultaneous equation.​

Answer 1

Answer:

A would take 40 days to fill the pool alone

B would take 24 days to fill the pool alone

Step-by-step explanation:

Let A and B be the rate of two taps

According to the question

15A+15B=1   (1)

20A+12B=1  (2)  

Multiply (1) by 12 and (2) by 15

180A+180B=12    (3)

300A+180B=15    (4)

Subtract (iii) from (iv) we get

120A=3

A= 40 /1

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A would take 40 days to fill the pool alone

20A+12B=1

1/2  +12B=1

12B=  1/2  

B=  24 /1

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B would take 24 days to fill the pool alone