two taps A and B can together fill the cistern in 9 3/8 hours if a tap A can take fill it in 25 hours how long will tap B take to fill the cistern
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Answer:B can fill the tAnk in x hours
According to condition both fill tank in 75 /8 hrs
Then it's one hour work will be
1/25 + 1/x = 8/75
1/x = 8/75 -1/25
1/x = 8-3/75
1/x = 5/75
Then x =15 then B take 15 hrs.
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