Two taps A and B can together fill the swimming pool in 15 days. Taps A and B are kept open for 12 days and then tap B is closed. It takes another 8 days for the pool to be filled . How many days does each tap require to fill the pool.
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Answer:
24 Days
Step-by-step explanation:
A + B do work in 15 days
A + B works together for 12 days means 15–12 = 3 days or 3 unit works remaining
which A has to done all alone…which he do in 8 days .
We can easily find efficency of A = 3/8
efficiency of b = 1–3/8 = 5/8
now , A do whole work in total work/efficiency
i.e. 15/3/8 = 40 days
B do whole work in 15/5/8 = 24 days
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